What are the solutions to the equation x^2-10x=-26 ?

The solutions to the equation x^2-10x=-26 are x=5+i,x=5-i

Find the zeros of x^2-10x=-26

The zeros of x^2-10x=-26 are x=5+i,x=5-i

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x^{2} - 10 x = - 26

x = 5 + i, x = 5 - i

Solution steps

x^{2} - 10 x = - 26

Move

26

to the left side

x^{2} - 10 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 26 : 2 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 i}{2 \cdot 1} : 5 + i

x = \frac{- ( - 10 ) - 2 i}{2 \cdot 1} : 5 - i

The solutions to the quadratic equation are:

x = 5 + i, x = 5 - i

3 p^{2} - 2 p - 5 = 0

x^{2} + 9 x = 0

(x + 1)^{3} - (x - 1)^{3} = 7

4 x^{2} + 16 x = 65

3 y^{2} - 144 = 0

What are the solutions to the equation x^2-10x=-26 ?
The solutions to the equation x^2-10x=-26 are x=5+i,x=5-i
Find the zeros of x^2-10x=-26
The zeros of x^2-10x=-26 are x=5+i,x=5-i