What are the solutions to the equation 49x^2-122.5x+49=0 ?

The solutions to the equation 49x^2-122.5x+49=0 are x=2,x= 1/2

Find the zeros of 49x^2-122.5x+49=0

The zeros of 49x^2-122.5x+49=0 are x=2,x= 1/2

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49 x^{2} - 122.5 x + 49 = 0

x = 2, x = \frac{1}{2}

Decimal Notation

x = 2, x = 0.5

Solution steps

49 x^{2} - 122.5 x + 49 = 0

Multiply both sides by

10

490 x^{2} - 1225 x + 490 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1225 ) \pm ( - 1225 ) ^{2} - 4 \cdot 490 \cdot 490}{2 \cdot 490}

(- 1225)^{2} - 4 \cdot 490 \cdot 490 = 735

x_{1, 2} = \frac{- ( - 1225 ) \pm 735}{2 \cdot 490}

Separate the solutions

x_{1} = \frac{- ( - 1225 ) + 735}{2 \cdot 490}, x_{2} = \frac{- ( - 1225 ) - 735}{2 \cdot 490}

x = \frac{- ( - 1225 ) + 735}{2 \cdot 490} : 2

x = \frac{- ( - 1225 ) - 735}{2 \cdot 490} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{2}

r^{2} + 25 r = 0

\frac{1}{4} x^{2} - x + 1 = 0

10 p^{2} = 7 p + 7

10 x^{2} + 23 x - 5 = 0

s^{2} + 6 s + 24 = 0

What are the solutions to the equation 49x^2-122.5x+49=0 ?
The solutions to the equation 49x^2-122.5x+49=0 are x=2,x= 1/2
Find the zeros of 49x^2-122.5x+49=0
The zeros of 49x^2-122.5x+49=0 are x=2,x= 1/2