What are the solutions to the equation s^2+6s+24=0 ?

The solutions to the equation s^2+6s+24=0 are s=-3+sqrt(15)i,s=-3-sqrt(15)i

Find the zeros of s^2+6s+24=0

The zeros of s^2+6s+24=0 are s=-3+sqrt(15)i,s=-3-sqrt(15)i

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s^{2} + 6 s + 24 = 0

s = - 3 + 15 i, s = - 3 - 15 i

Solution steps

s^{2} + 6 s + 24 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 24 : 215 i

s_{1, 2} = \frac{- 6 \pm 2 15 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 6 + 2 15 i}{2 \cdot 1}, s_{2} = \frac{- 6 - 2 15 i}{2 \cdot 1}

s = \frac{- 6 + 2 15 i}{2 \cdot 1} : - 3 + 15 i

s = \frac{- 6 - 2 15 i}{2 \cdot 1} : - 3 - 15 i

The solutions to the quadratic equation are:

s = - 3 + 15 i, s = - 3 - 15 i

36 x^{2} - 36 x + 2 = 0

9^{2} + 1 5^{2} = x^{2}

(x + 4)^{2} + (x - 3)^{2} = (x - 1)^{2} + 36

- 5 (6 x + 7) (3 x + 2) = 0

x, x^{2} + y^{2} - 2 x - 2 y + 11 = 0

What are the solutions to the equation s^2+6s+24=0 ?
The solutions to the equation s^2+6s+24=0 are s=-3+sqrt(15)i,s=-3-sqrt(15)i
Find the zeros of s^2+6s+24=0
The zeros of s^2+6s+24=0 are s=-3+sqrt(15)i,s=-3-sqrt(15)i