What are the solutions to the equation 10x^2+23x-5=0 ?

The solutions to the equation 10x^2+23x-5=0 are x= 1/5 ,x=-5/2

Find the zeros of 10x^2+23x-5=0

The zeros of 10x^2+23x-5=0 are x= 1/5 ,x=-5/2

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10 x^{2} + 23 x - 5 = 0

x = \frac{1}{5}, x = - \frac{5}{2}

Decimal Notation

x = 0.2, x = - 2.5

Solution steps

10 x^{2} + 23 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 10 ( - 5 )}{2 \cdot 10}

2 3^{2} - 4 \cdot 10 (- 5) = 27

x_{1, 2} = \frac{- 23 \pm 27}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 23 + 27}{2 \cdot 10}, x_{2} = \frac{- 23 - 27}{2 \cdot 10}

x = \frac{- 23 + 27}{2 \cdot 10} : \frac{1}{5}

x = \frac{- 23 - 27}{2 \cdot 10} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{5}{2}

s^{2} + 6 s + 24 = 0

36 x^{2} - 36 x + 2 = 0

9^{2} + 1 5^{2} = x^{2}

(x + 4)^{2} + (x - 3)^{2} = (x - 1)^{2} + 36

- 5 (6 x + 7) (3 x + 2) = 0

What are the solutions to the equation 10x^2+23x-5=0 ?
The solutions to the equation 10x^2+23x-5=0 are x= 1/5 ,x=-5/2
Find the zeros of 10x^2+23x-5=0
The zeros of 10x^2+23x-5=0 are x= 1/5 ,x=-5/2