What are the solutions to the equation v^2-5v-24=0 ?

The solutions to the equation v^2-5v-24=0 are v=8,v=-3

Find the zeros of v^2-5v-24=0

The zeros of v^2-5v-24=0 are v=8,v=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{2} - 5 v - 24 = 0

v = 8, v = - 3

Solution steps

v^{2} - 5 v - 24 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 24) = 11

v_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 1}, v_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 1}

v = \frac{- ( - 5 ) + 11}{2 \cdot 1} : 8

v = \frac{- ( - 5 ) - 11}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

v = 8, v = - 3

x, 5 y^{3} = x^{2}

y^{2} - y - 56 = 0

3 a^{2} - 17 = 31

2 x^{2} - 14 x + 49 = 0

x^{2} + 14 x + 36 = 0

What are the solutions to the equation v^2-5v-24=0 ?
The solutions to the equation v^2-5v-24=0 are v=8,v=-3
Find the zeros of v^2-5v-24=0
The zeros of v^2-5v-24=0 are v=8,v=-3