What are the solutions to the equation (x-2)2+x(x+1)=24 ?

The solutions to the equation (x-2)2+x(x+1)=24 are x=4,x=-7

Find the zeros of (x-2)2+x(x+1)=24

The zeros of (x-2)2+x(x+1)=24 are x=4,x=-7

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(x - 2) 2 + x (x + 1) = 24

x = 4, x = - 7

Solution steps

(x - 2) \cdot 2 + x (x + 1) = 24

Expand

(x - 2) \cdot 2 + x (x + 1) : x^{2} + 3 x - 4

x^{2} + 3 x - 4 = 24

Move

24

to the left side

x^{2} + 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 11}{2 \cdot 1}, x_{2} = \frac{- 3 - 11}{2 \cdot 1}

x = \frac{- 3 + 11}{2 \cdot 1} : 4

x = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 4, x = - 7

x^{2} + 8 x - 32 = 0

z, x^{3} z^{2} - 5 x y^{5} z = x^{2} + y^{3}

5 x^{2} - x + 6 = 5 - 7 x - 4 x^{2}

y, (x - 2)^{2} + (y + 3)^{2} = 4

y, (x - 2)^{2} + (y + 3)^{2} = 9

What are the solutions to the equation (x-2)2+x(x+1)=24 ?
The solutions to the equation (x-2)2+x(x+1)=24 are x=4,x=-7
Find the zeros of (x-2)2+x(x+1)=24
The zeros of (x-2)2+x(x+1)=24 are x=4,x=-7