What are the solutions to the equation m^2+6m+18=0 ?

The solutions to the equation m^2+6m+18=0 are m=-3+3i,m=-3-3i

Find the zeros of m^2+6m+18=0

The zeros of m^2+6m+18=0 are m=-3+3i,m=-3-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 6 m + 18 = 0

m = - 3 + 3 i, m = - 3 - 3 i

Solution steps

m^{2} + 6 m + 18 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 18 : 6 i

m_{1, 2} = \frac{- 6 \pm 6 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 6 + 6 i}{2 \cdot 1}, m_{2} = \frac{- 6 - 6 i}{2 \cdot 1}

m = \frac{- 6 + 6 i}{2 \cdot 1} : - 3 + 3 i

m = \frac{- 6 - 6 i}{2 \cdot 1} : - 3 - 3 i

The solutions to the quadratic equation are:

m = - 3 + 3 i, m = - 3 - 3 i

x^{2} + 7 x + \frac{49}{4} = 4

(x + 5)^{2} = 10 x + 50

3 x (5 - x) = x (7 - x)

x (2 x + \frac{1}{3}) - 5 x^{2} = 3 x - 2

4 (x^{2} - 1) = 21

What are the solutions to the equation m^2+6m+18=0 ?
The solutions to the equation m^2+6m+18=0 are m=-3+3i,m=-3-3i
Find the zeros of m^2+6m+18=0
The zeros of m^2+6m+18=0 are m=-3+3i,m=-3-3i