What are the solutions to the equation 3x(5-x)=x(7-x) ?

The solutions to the equation 3x(5-x)=x(7-x) are x=0,x=4

Find the zeros of 3x(5-x)=x(7-x)

The zeros of 3x(5-x)=x(7-x) are x=0,x=4

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3 x (5 - x) = x (7 - x)

x = 0, x = 4

Solution steps

3 x (5 - x) = x (7 - x)

Move

x (7 - x)

to the left side

3 x (5 - x) - x (7 - x) = 0

Factor

3 x (5 - x) - x (7 - x) : - 2 x (x - 4)

- 2 x (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = 0, x = 4

x (2 x + \frac{1}{3}) - 5 x^{2} = 3 x - 2

4 (x^{2} - 1) = 21

15 (2 a - 2) = 5 (a^{2} - 1)

2 n^{2} - 14 n + 3 = 3

s^{2} + 3 s + 4

What are the solutions to the equation 3x(5-x)=x(7-x) ?
The solutions to the equation 3x(5-x)=x(7-x) are x=0,x=4
Find the zeros of 3x(5-x)=x(7-x)
The zeros of 3x(5-x)=x(7-x) are x=0,x=4