What are the solutions to the equation x(x+3)=54 ?

The solutions to the equation x(x+3)=54 are x=6,x=-9

Find the zeros of x(x+3)=54

The zeros of x(x+3)=54 are x=6,x=-9

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x (x + 3) = 54

x = 6, x = - 9

Solution steps

x (x + 3) = 54

Expand

x (x + 3) : x^{2} + 3 x

x^{2} + 3 x = 54

Move

54

to the left side

x^{2} + 3 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 54) = 15

x_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 15}{2 \cdot 1}, x_{2} = \frac{- 3 - 15}{2 \cdot 1}

x = \frac{- 3 + 15}{2 \cdot 1} : 6

x = \frac{- 3 - 15}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 6, x = - 9

12 b^{2} - 27 = 0

x (x + 3) = - 2

3 x^{2} + 12 + 1 = 0

x^{2} + x - 56 = 0

- 144 + 7 x + x^{2} = 0

What are the solutions to the equation x(x+3)=54 ?
The solutions to the equation x(x+3)=54 are x=6,x=-9
Find the zeros of x(x+3)=54
The zeros of x(x+3)=54 are x=6,x=-9