What are the solutions to the equation 3+2x-x^2=3-x ?

The solutions to the equation 3+2x-x^2=3-x are x=0,x=3

Find the zeros of 3+2x-x^2=3-x

The zeros of 3+2x-x^2=3-x are x=0,x=3

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3 + 2 x - x^{2} = 3 - x

x = 0, x = 3

Solution steps

3 + 2 x - x^{2} = 3 - x

Move

x

to the left side

- x^{2} + 3 x + 3 = 3

Move

3

to the left side

- x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 1 )}, x_{2} = \frac{- 3 - 3}{2 ( - 1 )}

x = \frac{- 3 + 3}{2 ( - 1 )} : 0

x = \frac{- 3 - 3}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

(x + 7) (x - 5) = 0

(x - 1) (x - 2) + x (x - 2) + x (x - 1) = 0

- 3 n^{2} + 15 n + 18 = 0

- 3 x^{2} + 12 x - 1 = 0

x, 8 x^{2} - 16 x - 6 y^{2} + 24 y = 16

What are the solutions to the equation 3+2x-x^2=3-x ?
The solutions to the equation 3+2x-x^2=3-x are x=0,x=3
Find the zeros of 3+2x-x^2=3-x
The zeros of 3+2x-x^2=3-x are x=0,x=3