What are the solutions to the equation -3n^2+15n+18=0 ?

The solutions to the equation -3n^2+15n+18=0 are n=-1,n=6

Find the zeros of -3n^2+15n+18=0

The zeros of -3n^2+15n+18=0 are n=-1,n=6

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- 3 n^{2} + 15 n + 18 = 0

n = - 1, n = 6

Solution steps

- 3 n^{2} + 15 n + 18 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 3 ) \cdot 18}{2 ( - 3 )}

1 5^{2} - 4 (- 3) \cdot 18 = 21

n_{1, 2} = \frac{- 15 \pm 21}{2 ( - 3 )}

Separate the solutions

n_{1} = \frac{- 15 + 21}{2 ( - 3 )}, n_{2} = \frac{- 15 - 21}{2 ( - 3 )}

n = \frac{- 15 + 21}{2 ( - 3 )} : - 1

n = \frac{- 15 - 21}{2 ( - 3 )} : 6

The solutions to the quadratic equation are:

n = - 1, n = 6

- 3 x^{2} + 12 x - 1 = 0

x, 8 x^{2} - 16 x - 6 y^{2} + 24 y = 16

1 - 1.4 l + 0.6 l^{2} = 0

c (x) = 120 x - 40 x^{2}

x^{2} + 4 x - 9

What are the solutions to the equation -3n^2+15n+18=0 ?
The solutions to the equation -3n^2+15n+18=0 are n=-1,n=6
Find the zeros of -3n^2+15n+18=0
The zeros of -3n^2+15n+18=0 are n=-1,n=6