What are the solutions to the equation -3x^2+12x-1=0 ?

The solutions to the equation -3x^2+12x-1=0 are x=(6-sqrt(33))/3 ,x=(6+sqrt(33))/3

Find the zeros of -3x^2+12x-1=0

The zeros of -3x^2+12x-1=0 are x=(6-sqrt(33))/3 ,x=(6+sqrt(33))/3

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- 3 x^{2} + 12 x - 1 = 0

x = \frac{6 - 33}{3}, x = \frac{6 + 33}{3}

Decimal Notation

x = 0.08514 \dots, x = 3.91485 \dots

Solution steps

- 3 x^{2} + 12 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) ( - 1 )}{2 ( - 3 )}

1 2^{2} - 4 (- 3) (- 1) = 233

x_{1, 2} = \frac{- 12 \pm 2 33}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 33}{2 ( - 3 )}, x_{2} = \frac{- 12 - 2 33}{2 ( - 3 )}

x = \frac{- 12 + 2 33}{2 ( - 3 )} : \frac{6 - 33}{3}

x = \frac{- 12 - 2 33}{2 ( - 3 )} : \frac{6 + 33}{3}

The solutions to the quadratic equation are:

x = \frac{6 - 33}{3}, x = \frac{6 + 33}{3}

x, 8 x^{2} - 16 x - 6 y^{2} + 24 y = 16

1 - 1.4 l + 0.6 l^{2} = 0

c (x) = 120 x - 40 x^{2}

x^{2} + 4 x - 9

x^{2} + 4 x - 8

What are the solutions to the equation -3x^2+12x-1=0 ?
The solutions to the equation -3x^2+12x-1=0 are x=(6-sqrt(33))/3 ,x=(6+sqrt(33))/3
Find the zeros of -3x^2+12x-1=0
The zeros of -3x^2+12x-1=0 are x=(6-sqrt(33))/3 ,x=(6+sqrt(33))/3