What are the solutions to the equation 1-1.4l+0.6l^2=0 ?

The solutions to the equation 1-1.4l+0.6l^2=0 are l= 7/6+i(sqrt(11))/6 ,l= 7/6-i(sqrt(11))/6

Find the zeros of 1-1.4l+0.6l^2=0

The zeros of 1-1.4l+0.6l^2=0 are l= 7/6+i(sqrt(11))/6 ,l= 7/6-i(sqrt(11))/6

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1 - 1.4 l + 0.6 l^{2} = 0

l = \frac{7}{6} + i \frac{11}{6}, l = \frac{7}{6} - i \frac{11}{6}

Solution steps

1 - 1.4 l + 0.6 l^{2} = 0

Multiply both sides by

10

10 - 14 l + 6 l^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

6 l^{2} - 14 l + 10 = 0

Solve with the quadratic formula

l_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 6 \cdot 10}{2 \cdot 6}

Simplify

(- 14)^{2} - 4 \cdot 6 \cdot 10 : 211 i

l_{1, 2} = \frac{- ( - 14 ) \pm 2 11 i}{2 \cdot 6}

Separate the solutions

l_{1} = \frac{- ( - 14 ) + 2 11 i}{2 \cdot 6}, l_{2} = \frac{- ( - 14 ) - 2 11 i}{2 \cdot 6}

l = \frac{- ( - 14 ) + 2 11 i}{2 \cdot 6} : \frac{7}{6} + i \frac{11}{6}

l = \frac{- ( - 14 ) - 2 11 i}{2 \cdot 6} : \frac{7}{6} - i \frac{11}{6}

The solutions to the quadratic equation are:

l = \frac{7}{6} + i \frac{11}{6}, l = \frac{7}{6} - i \frac{11}{6}

c (x) = 120 x - 40 x^{2}

x^{2} + 4 x - 9

x^{2} + 4 x - 8

- x^{2} + 72 x = - 216 - 7 x^{2}

- 5 x^{2} + x + 4 = 0

What are the solutions to the equation 1-1.4l+0.6l^2=0 ?
The solutions to the equation 1-1.4l+0.6l^2=0 are l= 7/6+i(sqrt(11))/6 ,l= 7/6-i(sqrt(11))/6
Find the zeros of 1-1.4l+0.6l^2=0
The zeros of 1-1.4l+0.6l^2=0 are l= 7/6+i(sqrt(11))/6 ,l= 7/6-i(sqrt(11))/6