What are the solutions to the equation 3r^2+75=0 ?

The solutions to the equation 3r^2+75=0 are r=5i,r=-5i

Find the zeros of 3r^2+75=0

The zeros of 3r^2+75=0 are r=5i,r=-5i

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3 r^{2} + 75 = 0

r = 5 i, r = - 5 i

Solution steps

3 r^{2} + 75 = 0

Move

75

to the right side

3 r^{2} = - 75

Divide both sides by

3

r^{2} = - 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 25, r = - - 25

- 25 = 5 i

- - 25 = - 5 i

r = 5 i, r = - 5 i

3 t^{2} - 10 t + 4 = 0

3 x^{2} = - 7 x

- 3 (p + 2)^{2} = 12

x^{2} = 24 - 4 x

(x - 12) (x - 6) = 27

What are the solutions to the equation 3r^2+75=0 ?
The solutions to the equation 3r^2+75=0 are r=5i,r=-5i
Find the zeros of 3r^2+75=0
The zeros of 3r^2+75=0 are r=5i,r=-5i