What are the solutions to the equation -3(p+2)^2=12 ?

The solutions to the equation -3(p+2)^2=12 are p=2i-2,p=-2i-2

Find the zeros of -3(p+2)^2=12

The zeros of -3(p+2)^2=12 are p=2i-2,p=-2i-2

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- 3 (p + 2)^{2} = 12

p = 2 i - 2, p = - 2 i - 2

Solution steps

- 3 (p + 2)^{2} = 12

Divide both sides by

- 3

(p + 2)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

p + 2 = - 4 : p = 2 i - 2

Solve

p + 2 = - - 4 : p = - 2 i - 2

The solutions to the quadratic equation are:

p = 2 i - 2, p = - 2 i - 2

x^{2} = 24 - 4 x

(x - 12) (x - 6) = 27

- 16 t^{2} + 80 t + 60 = 0

- \frac{x ^{2}}{200} + x - 2 = 39

- 5 (x + 1) (x - 3) = 0

What are the solutions to the equation -3(p+2)^2=12 ?
The solutions to the equation -3(p+2)^2=12 are p=2i-2,p=-2i-2
Find the zeros of -3(p+2)^2=12
The zeros of -3(p+2)^2=12 are p=2i-2,p=-2i-2