What are the solutions to the equation 4x^2-16x+4=0 ?

The solutions to the equation 4x^2-16x+4=0 are x=2+sqrt(3),x=2-sqrt(3)

Find the zeros of 4x^2-16x+4=0

The zeros of 4x^2-16x+4=0 are x=2+sqrt(3),x=2-sqrt(3)

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4 x^{2} - 16 x + 4 = 0

x = 2 + 3, x = 2 - 3

Decimal Notation

x = 3.73205 \dots, x = 0.26794 \dots

Solution steps

4 x^{2} - 16 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 4 = 83

x_{1, 2} = \frac{- ( - 16 ) \pm 8 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 8 3}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 8 3}{2 \cdot 4}

x = \frac{- ( - 16 ) + 8 3}{2 \cdot 4} : 2 + 3

x = \frac{- ( - 16 ) - 8 3}{2 \cdot 4} : 2 - 3

The solutions to the quadratic equation are:

x = 2 + 3, x = 2 - 3

(x - 3)^{2} + (x + 4)^{2} - (x - 5)^{2} = 17 x + 24

(4 - m)^{2} - 4 (3) (3 m - 36) = 0

x (2 x - 3) = 9

2 x^{2} - 12 x + 23 = 0

x^{2} + 16 x + 8 = 0

What are the solutions to the equation 4x^2-16x+4=0 ?
The solutions to the equation 4x^2-16x+4=0 are x=2+sqrt(3),x=2-sqrt(3)
Find the zeros of 4x^2-16x+4=0
The zeros of 4x^2-16x+4=0 are x=2+sqrt(3),x=2-sqrt(3)