What are the solutions to the equation 2b^2-72=0 ?

The solutions to the equation 2b^2-72=0 are b=6,b=-6

Find the zeros of 2b^2-72=0

The zeros of 2b^2-72=0 are b=6,b=-6

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2 b^{2} - 72 = 0

b = 6, b = - 6

Solution steps

2 b^{2} - 72 = 0

Move

72

to the right side

2 b^{2} = 72

Divide both sides by

2

b^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 36, b = - 36

36 = 6

- 36 = - 6

b = 6, b = - 6

18 x^{2} - 66 x + 42 = 0

2 x - x^{2} = 3

3 x^{2} = 363

2 x^{2} = - 9 x + 3

6 = \frac{V ^{2}}{2 ( \frac{20}{3} )}

What are the solutions to the equation 2b^2-72=0 ?
The solutions to the equation 2b^2-72=0 are b=6,b=-6
Find the zeros of 2b^2-72=0
The zeros of 2b^2-72=0 are b=6,b=-6