What are the solutions to the equation x^2+(-282)=51 ?

The solutions to the equation x^2+(-282)=51 are x=3sqrt(37),x=-3sqrt(37)

Find the zeros of x^2+(-282)=51

The zeros of x^2+(-282)=51 are x=3sqrt(37),x=-3sqrt(37)

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x^{2} + (- 282) = 51

x = 337, x = - 337

Decimal Notation

x = 18.24828 \dots, x = - 18.24828 \dots

Solution steps

x^{2} + (- 282) = 51

Refine

x^{2} - 282 = 51

Move

282

to the right side

x^{2} = 333

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 333, x = - 333

333 = 337

- 333 = - 337

x = 337, x = - 337

x (x + 1) - 2 (x + 1) = 0

D^{2} + 9 = 0

x^{2} - 32 = 4 x

x^{2} + 16 x + 0 = 0

x^{2} - 9 x + 14 = 0

What are the solutions to the equation x^2+(-282)=51 ?
The solutions to the equation x^2+(-282)=51 are x=3sqrt(37),x=-3sqrt(37)
Find the zeros of x^2+(-282)=51
The zeros of x^2+(-282)=51 are x=3sqrt(37),x=-3sqrt(37)