What are the solutions to the equation x^2-32=4x ?

The solutions to the equation x^2-32=4x are x=8,x=-4

Find the zeros of x^2-32=4x

The zeros of x^2-32=4x are x=8,x=-4

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x^{2} - 32 = 4 x

x = 8, x = - 4

Solution steps

x^{2} - 32 = 4 x

Move

4 x

to the left side

x^{2} - 32 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 32) = 12

x_{1, 2} = \frac{- ( - 4 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 12}{2 \cdot 1}

x = \frac{- ( - 4 ) + 12}{2 \cdot 1} : 8

x = \frac{- ( - 4 ) - 12}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 8, x = - 4

x^{2} + 16 x + 0 = 0

x^{2} - 9 x + 14 = 0

x, 1200 = x^{2} + 4 x y

s^{2} + 4 s + 6

x^{2} = 50 (x + 100)

What are the solutions to the equation x^2-32=4x ?
The solutions to the equation x^2-32=4x are x=8,x=-4
Find the zeros of x^2-32=4x
The zeros of x^2-32=4x are x=8,x=-4