What are the solutions to the equation x^2+16x+0=0 ?

The solutions to the equation x^2+16x+0=0 are x=0,x=-16

Find the zeros of x^2+16x+0=0

The zeros of x^2+16x+0=0 are x=0,x=-16

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x^{2} + 16 x + 0 = 0

x = 0, x = - 16

Solution steps

x^{2} + 16 x + 0 = 0

Refine

x^{2} + 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 0 = 16

x_{1, 2} = \frac{- 16 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 16}{2 \cdot 1}, x_{2} = \frac{- 16 - 16}{2 \cdot 1}

x = \frac{- 16 + 16}{2 \cdot 1} : 0

x = \frac{- 16 - 16}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 0, x = - 16

x^{2} - 9 x + 14 = 0

x, 1200 = x^{2} + 4 x y

s^{2} + 4 s + 6

x^{2} = 50 (x + 100)

c^{2} - 13 c - 14 = 0

What are the solutions to the equation x^2+16x+0=0 ?
The solutions to the equation x^2+16x+0=0 are x=0,x=-16
Find the zeros of x^2+16x+0=0
The zeros of x^2+16x+0=0 are x=0,x=-16