What are the solutions to the equation x^2=50(x+100) ?

The solutions to the equation x^2=50(x+100) are x=100,x=-50

Find the zeros of x^2=50(x+100)

The zeros of x^2=50(x+100) are x=100,x=-50

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x^{2} = 50 (x + 100)

x = 100, x = - 50

Solution steps

x^{2} = 50 (x + 100)

Expand

50 (x + 100) : 50 x + 5000

x^{2} = 50 x + 5000

Move

5000

to the left side

x^{2} - 5000 = 50 x

Move

50 x

to the left side

x^{2} - 5000 - 50 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 50 x - 5000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 50 ) \pm ( - 50 ) ^{2} - 4 \cdot 1 \cdot ( - 5000 )}{2 \cdot 1}

(- 50)^{2} - 4 \cdot 1 \cdot (- 5000) = 150

x_{1, 2} = \frac{- ( - 50 ) \pm 150}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 50 ) + 150}{2 \cdot 1}, x_{2} = \frac{- ( - 50 ) - 150}{2 \cdot 1}

x = \frac{- ( - 50 ) + 150}{2 \cdot 1} : 100

x = \frac{- ( - 50 ) - 150}{2 \cdot 1} : - 50

The solutions to the quadratic equation are:

x = 100, x = - 50

c^{2} - 13 c - 14 = 0

4 x^{2} - x - 4 = 0

x^{2} + 6 x + 6 = 0

a^{2} + 1^{2} = 3^{2}

x, 3 x^{2} + 2 x y - 4 y = 0

What are the solutions to the equation x^2=50(x+100) ?
The solutions to the equation x^2=50(x+100) are x=100,x=-50
Find the zeros of x^2=50(x+100)
The zeros of x^2=50(x+100) are x=100,x=-50