What are the solutions to the equation solvefor x,x^2-14x+49=0 ?

The solutions to the equation solvefor x,x^2-14x+49=0 are x=7

Find the zeros of solvefor x,x^2-14x+49=0

The zeros of solvefor x,x^2-14x+49=0 are x=7

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x, x^{2} - 14 x + 49 = 0

x = 7

Solution steps

x^{2} - 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

x = 7

The solution to the quadratic equation is:

x = 7

8 + 2 m^{2} = 32

t^{2} - 8 t = 0

13 - 6 x = (2 x - 5)^{2} + 3

x, - \frac{1}{y} = x - 4 x^{2}

0 = - 4.9 t^{2} + 4.25 t + 100

What are the solutions to the equation solvefor x,x^2-14x+49=0 ?
The solutions to the equation solvefor x,x^2-14x+49=0 are x=7
Find the zeros of solvefor x,x^2-14x+49=0
The zeros of solvefor x,x^2-14x+49=0 are x=7