What are the solutions to the equation x^2-23x+102=0 ?

The solutions to the equation x^2-23x+102=0 are x=17,x=6

Find the zeros of x^2-23x+102=0

The zeros of x^2-23x+102=0 are x=17,x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 23 x + 102 = 0

x = 17, x = 6

Solution steps

x^{2} - 23 x + 102 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 1 \cdot 102}{2 \cdot 1}

(- 23)^{2} - 4 \cdot 1 \cdot 102 = 11

x_{1, 2} = \frac{- ( - 23 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 23 ) - 11}{2 \cdot 1}

x = \frac{- ( - 23 ) + 11}{2 \cdot 1} : 17

x = \frac{- ( - 23 ) - 11}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 17, x = 6

x^{2} + 10 x + 45 = 0

x^{2} - 19 x + 23 = 0

y^{2} = 4 y + 12

x^{2} + 12 x - 4

t, d = - 3 t^{2} + 12 t - 7

What are the solutions to the equation x^2-23x+102=0 ?
The solutions to the equation x^2-23x+102=0 are x=17,x=6
Find the zeros of x^2-23x+102=0
The zeros of x^2-23x+102=0 are x=17,x=6