What are the solutions to the equation (2x+2)(x)=60 ?

The solutions to the equation (2x+2)(x)=60 are x=5,x=-6

Find the zeros of (2x+2)(x)=60

The zeros of (2x+2)(x)=60 are x=5,x=-6

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(2 x + 2) (x) = 60

x = 5, x = - 6

Solution steps

(2 x + 2) (x) = 60

Expand

(2 x + 2) (x) : 2 x^{2} + 2 x

2 x^{2} + 2 x = 60

Move

60

to the left side

2 x^{2} + 2 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 60) = 22

x_{1, 2} = \frac{- 2 \pm 22}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 22}{2 \cdot 2}, x_{2} = \frac{- 2 - 22}{2 \cdot 2}

x = \frac{- 2 + 22}{2 \cdot 2} : 5

x = \frac{- 2 - 22}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

x = 5, x = - 6

4 x^{2} + 24 x + 13 = 2 x^{2} + 6 x

x^{2} + 8 x - 35 = 0

x^{2} + 15 x + 64 = 0

(x - 5)^{2} = 2

12 x^{2} + 12 x - 72 = 0

What are the solutions to the equation (2x+2)(x)=60 ?
The solutions to the equation (2x+2)(x)=60 are x=5,x=-6
Find the zeros of (2x+2)(x)=60
The zeros of (2x+2)(x)=60 are x=5,x=-6