What are the solutions to the equation x^2+40^2=41^2 ?

The solutions to the equation x^2+40^2=41^2 are x=9,x=-9

Find the zeros of x^2+40^2=41^2

The zeros of x^2+40^2=41^2 are x=9,x=-9

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x^{2} + 4 0^{2} = 4 1^{2}

x = 9, x = - 9

Solution steps

x^{2} + 4 0^{2} = 4 1^{2}

Move

4 0^{2}

to the right side

x^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

- x^{2} + 6 x + 16 = 0

s, s^{2} + 2 s + 2 = 0

4 x^{2} + 64 x + 240 = 0

7 x^{2} - 2 x - 32 = 0

x, x^{2} + y x - x + y + 4 = 0

What are the solutions to the equation x^2+40^2=41^2 ?
The solutions to the equation x^2+40^2=41^2 are x=9,x=-9
Find the zeros of x^2+40^2=41^2
The zeros of x^2+40^2=41^2 are x=9,x=-9