What are the solutions to the equation -x^2+6x+16=0 ?

The solutions to the equation -x^2+6x+16=0 are x=-2,x=8

Find the zeros of -x^2+6x+16=0

The zeros of -x^2+6x+16=0 are x=-2,x=8

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- x^{2} + 6 x + 16 = 0

x = - 2, x = 8

Solution steps

- x^{2} + 6 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 16}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 16 = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 ( - 1 )}, x_{2} = \frac{- 6 - 10}{2 ( - 1 )}

x = \frac{- 6 + 10}{2 ( - 1 )} : - 2

x = \frac{- 6 - 10}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = - 2, x = 8

s, s^{2} + 2 s + 2 = 0

4 x^{2} + 64 x + 240 = 0

7 x^{2} - 2 x - 32 = 0

x, x^{2} + y x - x + y + 4 = 0

p^{2} - p - 12 = 0

What are the solutions to the equation -x^2+6x+16=0 ?
The solutions to the equation -x^2+6x+16=0 are x=-2,x=8
Find the zeros of -x^2+6x+16=0
The zeros of -x^2+6x+16=0 are x=-2,x=8