What are the solutions to the equation 0=-0.1x^2-0.2x+8 ?

The solutions to the equation 0=-0.1x^2-0.2x+8 are x=-10,x=8

Find the zeros of 0=-0.1x^2-0.2x+8

The zeros of 0=-0.1x^2-0.2x+8 are x=-10,x=8

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0 = - 0.1 x^{2} - 0.2 x + 8

x = - 10, x = 8

Solution steps

0 = - 0.1 x^{2} - 0.2 x + 8

Multiply both sides by

10

0 = - x^{2} - 2 x + 80

Switch sides

- x^{2} - 2 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 80}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 80 = 18

x_{1, 2} = \frac{- ( - 2 ) \pm 18}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 18}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 18}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 18}{2 ( - 1 )} : - 10

x = \frac{- ( - 2 ) - 18}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = - 10, x = 8

9 x^{2} + 9 x - 2 = 0

x^{2} + 13 x + 31 = 0

- 16 t^{2} + 96 t + 432 = 0

0 = 6 x^{2} + x - 5

128 = 96 t - 16 t^{2}

What are the solutions to the equation 0=-0.1x^2-0.2x+8 ?
The solutions to the equation 0=-0.1x^2-0.2x+8 are x=-10,x=8
Find the zeros of 0=-0.1x^2-0.2x+8
The zeros of 0=-0.1x^2-0.2x+8 are x=-10,x=8