What are the solutions to the equation 3b^2-3=8b ?

The solutions to the equation 3b^2-3=8b are b=3,b=-1/3

Find the zeros of 3b^2-3=8b

The zeros of 3b^2-3=8b are b=3,b=-1/3

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3 b^{2} - 3 = 8 b

b = 3, b = - \frac{1}{3}

Decimal Notation

b = 3, b = - 0.33333 \dots

Solution steps

3 b^{2} - 3 = 8 b

Move

8 b

to the left side

3 b^{2} - 3 - 8 b = 0

Write in the standard form

a x^{2} + b x + c = 0

3 b^{2} - 8 b - 3 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 3) = 10

b_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 3}, b_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 3}

b = \frac{- ( - 8 ) + 10}{2 \cdot 3} : 3

b = \frac{- ( - 8 ) - 10}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

b = 3, b = - \frac{1}{3}

5 x^{2} = - 9 x

2 x - x^{2} + 8 = - 2 x^{2} - 5 x

x^{2} + 2 a x + a^{2} - b^{2} = 0

5 x^{2} + 8 = - 12 x

4 X^{2} - 8 X + 3 = 0

What are the solutions to the equation 3b^2-3=8b ?
The solutions to the equation 3b^2-3=8b are b=3,b=-1/3
Find the zeros of 3b^2-3=8b
The zeros of 3b^2-3=8b are b=3,b=-1/3