What are the solutions to the equation x^2+2ax+a^2-b^2=0 ?

The solutions to the equation x^2+2ax+a^2-b^2=0 are x=-a+b,x=-a-b

Find the zeros of x^2+2ax+a^2-b^2=0

The zeros of x^2+2ax+a^2-b^2=0 are x=-a+b,x=-a-b

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x^{2} + 2 a x + a^{2} - b^{2} = 0

x = - a + b, x = - a - b

Solution steps

x^{2} + 2 a x + a^{2} - b^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 a \pm ( 2 a ) ^{2} - 4 \cdot 1 \cdot ( a ^{2} - b ^{2} )}{2 \cdot 1}

Simplify

(2 a)^{2} - 4 \cdot 1 \cdot (a^{2} - b^{2}) : 2 b

x_{1, 2} = \frac{- 2 a \pm 2 b}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 a + 2 b}{2 \cdot 1}, x_{2} = \frac{- 2 a - 2 b}{2 \cdot 1}

x = \frac{- 2 a + 2 b}{2 \cdot 1} : - a + b

x = \frac{- 2 a - 2 b}{2 \cdot 1} : - a - b

The solutions to the quadratic equation are:

x = - a + b, x = - a - b

5 x^{2} + 8 = - 12 x

4 X^{2} - 8 X + 3 = 0

6 x^{2} - 5 x + 7 = 0

x, 3 x^{2} - 2 x - 1 = 0

λ^{2} - λ + 1 = 0

What are the solutions to the equation x^2+2ax+a^2-b^2=0 ?
The solutions to the equation x^2+2ax+a^2-b^2=0 are x=-a+b,x=-a-b
Find the zeros of x^2+2ax+a^2-b^2=0
The zeros of x^2+2ax+a^2-b^2=0 are x=-a+b,x=-a-b