What are the solutions to the equation solvefor x,z=4-x^2-2y^2 ?

The solutions to the equation solvefor x,z=4-x^2-2y^2 are x=sqrt(-z-2y^2+4),x=-sqrt(-z-2y^2+4)

Find the zeros of solvefor x,z=4-x^2-2y^2

The zeros of solvefor x,z=4-x^2-2y^2 are x=sqrt(-z-2y^2+4),x=-sqrt(-z-2y^2+4)

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solve for

x, z = 4 - x^{2} - 2 y^{2}

x = - z - 2 y^{2} + 4, x = - - z - 2 y^{2} + 4

Solution steps

z = 4 - x^{2} - 2 y^{2}

Switch sides

4 - x^{2} - 2 y^{2} = z

Move

2 y^{2}

to the right side

4 - x^{2} = z + 2 y^{2}

Move

4

to the right side

- x^{2} = z + 2 y^{2} - 4

Divide both sides by

- 1

x^{2} = - z - 2 y^{2} + 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - z - 2 y^{2} + 4, x = - - z - 2 y^{2} + 4

x, x^{2} + m x + 7 = 0

5 b^{2} + 4 b + 4 = 0

\frac{1}{16} x^{2} + x + 4 = 0

x^{2} + 28 x

1 + 4 + 7 + 10 (3 n - 2) = \frac{n ( 3 n - 1 )}{2}

What are the solutions to the equation solvefor x,z=4-x^2-2y^2 ?
The solutions to the equation solvefor x,z=4-x^2-2y^2 are x=sqrt(-z-2y^2+4),x=-sqrt(-z-2y^2+4)
Find the zeros of solvefor x,z=4-x^2-2y^2
The zeros of solvefor x,z=4-x^2-2y^2 are x=sqrt(-z-2y^2+4),x=-sqrt(-z-2y^2+4)