What are the solutions to the equation solvefor b,y=(a-b/x)^2 ?

The solutions to the equation solvefor b,y=(a-b/x)^2 are b=-xsqrt(y)+ax,b=xsqrt(y)+ax;\quad x\ne 0

Find the zeros of solvefor b,y=(a-b/x)^2

The zeros of solvefor b,y=(a-b/x)^2 are b=-xsqrt(y)+ax,b=xsqrt(y)+ax;\quad x\ne 0

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solve for

b, y = (a - \frac{b}{x})^{2}

b = - x y + a x, b = x y + a x; x \neq = 0

Solution steps

y = (a - \frac{b}{x})^{2}

Switch sides

(a - \frac{b}{x})^{2} = y

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a - \frac{b}{x} = y : b = - x y + a x; x \neq = 0

Solve

a - \frac{b}{x} = - y : b = x y + a x; x \neq = 0

The solutions to the quadratic equation are:

b = - x y + a x, b = x y + a x; x \neq = 0

2 x^{2} - 7 x = 0

x^{2} - 12 x + 13 = 0

- 0.5 x^{2} + 40 x - 300 = 15000

2 x^{2} + b x + c = 0

x^{2} - 2 x - 4 = 0

What are the solutions to the equation solvefor b,y=(a-b/x)^2 ?
The solutions to the equation solvefor b,y=(a-b/x)^2 are b=-xsqrt(y)+ax,b=xsqrt(y)+ax;\quad x\ne 0
Find the zeros of solvefor b,y=(a-b/x)^2
The zeros of solvefor b,y=(a-b/x)^2 are b=-xsqrt(y)+ax,b=xsqrt(y)+ax;\quad x\ne 0