What are the solutions to the equation t^2-6t+5=0 ?

The solutions to the equation t^2-6t+5=0 are t=5,t=1

Find the zeros of t^2-6t+5=0

The zeros of t^2-6t+5=0 are t=5,t=1

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t^{2} - 6 t + 5 = 0

t = 5, t = 1

Solution steps

t^{2} - 6 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

t_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

t = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

t = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

t = 5, t = 1

16 (x + 5)^{2} = 1

n^{2} + n - 6 = 0

0 = 2 x^{2} - 11 x + 5

x (x + 2) = 168

x^{2} + 16 = 10 x

What are the solutions to the equation t^2-6t+5=0 ?
The solutions to the equation t^2-6t+5=0 are t=5,t=1
Find the zeros of t^2-6t+5=0
The zeros of t^2-6t+5=0 are t=5,t=1