What are the solutions to the equation 3g^2+6g+3=0 ?

The solutions to the equation 3g^2+6g+3=0 are g=-1

Find the zeros of 3g^2+6g+3=0

The zeros of 3g^2+6g+3=0 are g=-1

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3 g^{2} + 6 g + 3 = 0

g = - 1

Solution steps

3 g^{2} + 6 g + 3 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 3 = 0

g_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 3}

g = \frac{- 6}{2 \cdot 3}

\frac{- 6}{2 \cdot 3} = - 1

g = - 1

The solution to the quadratic equation is:

g = - 1

2 x^{2} - 5 x + 2 = 0

t^{2} + t = 0

x^{2} - 8 x = - 20

x^{2} + x + 9 = 0

16 - x^{2} = - 20

What are the solutions to the equation 3g^2+6g+3=0 ?
The solutions to the equation 3g^2+6g+3=0 are g=-1
Find the zeros of 3g^2+6g+3=0
The zeros of 3g^2+6g+3=0 are g=-1