What are the solutions to the equation completesquare x^2+7x-5=0 ?

The solutions to the equation completesquare x^2+7x-5=0 are x=(sqrt(69)-7)/2 ,x=(-sqrt(69)-7)/2

Find the zeros of completesquare x^2+7x-5=0

The zeros of completesquare x^2+7x-5=0 are x=(sqrt(69)-7)/2 ,x=(-sqrt(69)-7)/2

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x^{2} + 7 x - 5 = 0

x = \frac{69 - 7}{2}, x = \frac{- 69 - 7}{2}

Decimal Notation

x = 0.65331 \dots, x = - 7.65331 \dots

Solution steps

x^{2} + 7 x - 5 = 0

Move

5

to the right side

x^{2} + 7 x = 5

Rewrite in the form

(x + a)^{2} = b

(x + \frac{7}{2})^{2} = \frac{69}{4}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{7}{2} = \frac{69}{4} : x = \frac{69 - 7}{2}

Solve

x + \frac{7}{2} = - \frac{69}{4} : x = \frac{- 69 - 7}{2}

The solutions to the quadratic equation are:

x = \frac{69 - 7}{2}, x = \frac{- 69 - 7}{2}

(x - 1) (x - 3) = 5

4 n^{2} + 1 = 157

y, 10 x^{2} - 3 y^{2} = 10

119.286 - 20 x + 7.5 x^{2} = 0

5 x^{2} - 25 x + 12

What are the solutions to the equation completesquare x^2+7x-5=0 ?
The solutions to the equation completesquare x^2+7x-5=0 are x=(sqrt(69)-7)/2 ,x=(-sqrt(69)-7)/2
Find the zeros of completesquare x^2+7x-5=0
The zeros of completesquare x^2+7x-5=0 are x=(sqrt(69)-7)/2 ,x=(-sqrt(69)-7)/2