What are the solutions to the equation 36pi=4pir^2 ?

The solutions to the equation 36pi=4pir^2 are r=-3,r=3

Find the zeros of 36pi=4pir^2

The zeros of 36pi=4pir^2 are r=-3,r=3

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36 π = 4 π r^{2}

r = - 3, r = 3

Solution steps

36 π = 4 π r^{2}

Move

4 π r^{2}

to the left side

36 π - 4 π r^{2} = 0

Factor

36 π - 4 π r^{2} : - 4 π (r + 3) (r - 3)

- 4 π (r + 3) (r - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r + 3 = 0 or r - 3 = 0

Solve

r + 3 = 0 : r = - 3

Solve

r - 3 = 0 : r = 3

The solutions to the quadratic equation are:

r = - 3, r = 3

2 x^{2} - 8 x = 0

p, q = 400 - p^{2}

y = - \frac{1}{20} y^{2}

124 = 0.006 a^{2} - 0.02 a + 120

- x^{2} - 2 x + 7 = - 17

What are the solutions to the equation 36pi=4pir^2 ?
The solutions to the equation 36pi=4pir^2 are r=-3,r=3
Find the zeros of 36pi=4pir^2
The zeros of 36pi=4pir^2 are r=-3,r=3