What are the solutions to the equation x^2+64x-320000=0 ?

The solutions to the equation x^2+64x-320000=0 are x=16(sqrt(1254)-2),x=-16(2+sqrt(1254))

Find the zeros of x^2+64x-320000=0

The zeros of x^2+64x-320000=0 are x=16(sqrt(1254)-2),x=-16(2+sqrt(1254))

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x^{2} + 64 x - 320000 = 0

x = 16 (1254 - 2), x = - 16 (2 + 1254)

Decimal Notation

x = 534.58979 \dots, x = - 598.58979 \dots

Solution steps

x^{2} + 64 x - 320000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 \cdot 1 \cdot ( - 320000 )}{2 \cdot 1}

6 4^{2} - 4 \cdot 1 \cdot (- 320000) = 321254

x_{1, 2} = \frac{- 64 \pm 32 1254}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 64 + 32 1254}{2 \cdot 1}, x_{2} = \frac{- 64 - 32 1254}{2 \cdot 1}

x = \frac{- 64 + 32 1254}{2 \cdot 1} : 16 (1254 - 2)

x = \frac{- 64 - 32 1254}{2 \cdot 1} : - 16 (2 + 1254)

The solutions to the quadratic equation are:

x = 16 (1254 - 2), x = - 16 (2 + 1254)

x^{2} - 8 x + 13 = 0

9 x^{2} + 14 = 65 x

x^{2} - 5 x + n + 2 = 0

- (x - 2)^{2} + 16 = 0

6 - x^{2} + 8 x = 5 + 4 x

What are the solutions to the equation x^2+64x-320000=0 ?
The solutions to the equation x^2+64x-320000=0 are x=16(sqrt(1254)-2),x=-16(2+sqrt(1254))
Find the zeros of x^2+64x-320000=0
The zeros of x^2+64x-320000=0 are x=16(sqrt(1254)-2),x=-16(2+sqrt(1254))