What are the solutions to the equation x^2+bx+16=0 ?

The solutions to the equation x^2+bx+16=0 are x=(-b+sqrt(b^2-64))/2 ,x=(-b-sqrt(b^2-64))/2

Find the zeros of x^2+bx+16=0

The zeros of x^2+bx+16=0 are x=(-b+sqrt(b^2-64))/2 ,x=(-b-sqrt(b^2-64))/2

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x^{2} + b x + 16 = 0

x = \frac{- b + b ^{2} - 64}{2}, x = \frac{- b - b ^{2} - 64}{2}

Solution steps

x^{2} + b x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- b \pm b ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

Simplify

b^{2} - 4 \cdot 1 \cdot 16 : b^{2} - 64

x_{1, 2} = \frac{- b \pm b ^{2} - 64}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- b + b ^{2} - 64}{2 \cdot 1}, x_{2} = \frac{- b - b ^{2} - 64}{2 \cdot 1}

x = \frac{- b + b ^{2} - 64}{2 \cdot 1} : \frac{- b + b ^{2} - 64}{2}

x = \frac{- b - b ^{2} - 64}{2 \cdot 1} : \frac{- b - b ^{2} - 64}{2}

The solutions to the quadratic equation are:

x = \frac{- b + b ^{2} - 64}{2}, x = \frac{- b - b ^{2} - 64}{2}

4 x^{2} - 11 x + 1 = 0

a x^{2} + 8 x + c = 0

x^{2} - 12 x + 56 = 0

x^{2} - 10 x - 3 = 5

x, x^{2} - 2 = 0

What are the solutions to the equation x^2+bx+16=0 ?
The solutions to the equation x^2+bx+16=0 are x=(-b+sqrt(b^2-64))/2 ,x=(-b-sqrt(b^2-64))/2
Find the zeros of x^2+bx+16=0
The zeros of x^2+bx+16=0 are x=(-b+sqrt(b^2-64))/2 ,x=(-b-sqrt(b^2-64))/2