What are the solutions to the equation 9x^2-40x+16=0 ?

The solutions to the equation 9x^2-40x+16=0 are x=4,x= 4/9

Find the zeros of 9x^2-40x+16=0

The zeros of 9x^2-40x+16=0 are x=4,x= 4/9

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9 x^{2} - 40 x + 16 = 0

x = 4, x = \frac{4}{9}

Decimal Notation

x = 4, x = 0.44444 \dots

Solution steps

9 x^{2} - 40 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 9 \cdot 16}{2 \cdot 9}

(- 40)^{2} - 4 \cdot 9 \cdot 16 = 32

x_{1, 2} = \frac{- ( - 40 ) \pm 32}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 32}{2 \cdot 9}, x_{2} = \frac{- ( - 40 ) - 32}{2 \cdot 9}

x = \frac{- ( - 40 ) + 32}{2 \cdot 9} : 4

x = \frac{- ( - 40 ) - 32}{2 \cdot 9} : \frac{4}{9}

The solutions to the quadratic equation are:

x = 4, x = \frac{4}{9}

x^{2} = 3^{2} + 1^{2}

4 x^{2} - 56 x + 192 = 0

(4 x - 1) (x - 3) = 15

a^{2} + 1 0^{2} = 2 6^{2}

0 = 3 x^{2} - 14 x

What are the solutions to the equation 9x^2-40x+16=0 ?
The solutions to the equation 9x^2-40x+16=0 are x=4,x= 4/9
Find the zeros of 9x^2-40x+16=0
The zeros of 9x^2-40x+16=0 are x=4,x= 4/9