What are the solutions to the equation -37x+12x^2-79=0 ?

The solutions to the equation -37x+12x^2-79=0 are x=(37+sqrt(5161))/(24),x=(37-sqrt(5161))/(24)

Find the zeros of -37x+12x^2-79=0

The zeros of -37x+12x^2-79=0 are x=(37+sqrt(5161))/(24),x=(37-sqrt(5161))/(24)

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- 37 x + 12 x^{2} - 79 = 0

x = \frac{37 + 5161}{24}, x = \frac{37 - 5161}{24}

Decimal Notation

x = 4.53500 \dots, x = - 1.45167 \dots

Solution steps

- 37 x + 12 x^{2} - 79 = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 37 x - 79 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 37 ) \pm ( - 37 ) ^{2} - 4 \cdot 12 ( - 79 )}{2 \cdot 12}

(- 37)^{2} - 4 \cdot 12 (- 79) = 5161

x_{1, 2} = \frac{- ( - 37 ) \pm 5161}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 37 ) + 5161}{2 \cdot 12}, x_{2} = \frac{- ( - 37 ) - 5161}{2 \cdot 12}

x = \frac{- ( - 37 ) + 5161}{2 \cdot 12} : \frac{37 + 5161}{24}

x = \frac{- ( - 37 ) - 5161}{2 \cdot 12} : \frac{37 - 5161}{24}

The solutions to the quadratic equation are:

x = \frac{37 + 5161}{24}, x = \frac{37 - 5161}{24}

3 x^{2} + 4 x = 3

3 x^{2} + 4 x = 7

3 x^{2} = 9 x - 5

- 5 x^{2} - 2 x + 9 = - 4 x^{2}

(z + 2)^{2} = 2

What are the solutions to the equation -37x+12x^2-79=0 ?
The solutions to the equation -37x+12x^2-79=0 are x=(37+sqrt(5161))/(24),x=(37-sqrt(5161))/(24)
Find the zeros of -37x+12x^2-79=0
The zeros of -37x+12x^2-79=0 are x=(37+sqrt(5161))/(24),x=(37-sqrt(5161))/(24)