What are the solutions to the equation 9x^2-3x-8=-10 ?

The solutions to the equation 9x^2-3x-8=-10 are x= 1/6+i(sqrt(7))/6 ,x= 1/6-i(sqrt(7))/6

Find the zeros of 9x^2-3x-8=-10

The zeros of 9x^2-3x-8=-10 are x= 1/6+i(sqrt(7))/6 ,x= 1/6-i(sqrt(7))/6

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9 x^{2} - 3 x - 8 = - 10

x = \frac{1}{6} + i \frac{7}{6}, x = \frac{1}{6} - i \frac{7}{6}

Solution steps

9 x^{2} - 3 x - 8 = - 10

Move

10

to the left side

9 x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 \cdot 2}{2 \cdot 9}

Simplify

(- 3)^{2} - 4 \cdot 9 \cdot 2 : 37 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 7 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 7 i}{2 \cdot 9}, x_{2} = \frac{- ( - 3 ) - 3 7 i}{2 \cdot 9}

x = \frac{- ( - 3 ) + 3 7 i}{2 \cdot 9} : \frac{1}{6} + i \frac{7}{6}

x = \frac{- ( - 3 ) - 3 7 i}{2 \cdot 9} : \frac{1}{6} - i \frac{7}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{7}{6}, x = \frac{1}{6} - i \frac{7}{6}

2 x^{2} + 4 x - 6 = 0

x^{2} - 4 = 1

x^{2} - 4 = 2

2 x^{2} + 4 x - 3 = 0

x^{2} + 6 x + 8 = 35

What are the solutions to the equation 9x^2-3x-8=-10 ?
The solutions to the equation 9x^2-3x-8=-10 are x= 1/6+i(sqrt(7))/6 ,x= 1/6-i(sqrt(7))/6
Find the zeros of 9x^2-3x-8=-10
The zeros of 9x^2-3x-8=-10 are x= 1/6+i(sqrt(7))/6 ,x= 1/6-i(sqrt(7))/6