What are the solutions to the equation (3x-2)(2x+5)=0 ?

The solutions to the equation (3x-2)(2x+5)=0 are x= 2/3 ,x=-5/2

Find the zeros of (3x-2)(2x+5)=0

The zeros of (3x-2)(2x+5)=0 are x= 2/3 ,x=-5/2

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(3 x - 2) (2 x + 5) = 0

x = \frac{2}{3}, x = - \frac{5}{2}

Decimal Notation

x = 0.66666 \dots, x = - 2.5

Solution steps

(3 x - 2) (2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or 2 x + 5 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{5}{2}

\frac{x}{2} \cdot \frac{x}{5} = 160

A (x) = 2 x^{2} + 20 x

x^{2} + x + \frac{5}{4}

(x - 1)^{2} + 4 = 0

x, y = 24 - 6 x^{2}

What are the solutions to the equation (3x-2)(2x+5)=0 ?
The solutions to the equation (3x-2)(2x+5)=0 are x= 2/3 ,x=-5/2
Find the zeros of (3x-2)(2x+5)=0
The zeros of (3x-2)(2x+5)=0 are x= 2/3 ,x=-5/2