What are the solutions to the equation 5x^2+17x+16=0 ?

The solutions to the equation 5x^2+17x+16=0 are x=-17/10+i(sqrt(31))/(10),x=-17/10-i(sqrt(31))/(10)

Find the zeros of 5x^2+17x+16=0

The zeros of 5x^2+17x+16=0 are x=-17/10+i(sqrt(31))/(10),x=-17/10-i(sqrt(31))/(10)

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5 x^{2} + 17 x + 16 = 0

x = - \frac{17}{10} + i \frac{31}{10}, x = - \frac{17}{10} - i \frac{31}{10}

Solution steps

5 x^{2} + 17 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 5 \cdot 16}{2 \cdot 5}

Simplify

1 7^{2} - 4 \cdot 5 \cdot 16 : 31 i

x_{1, 2} = \frac{- 17 \pm 31 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 17 + 31 i}{2 \cdot 5}, x_{2} = \frac{- 17 - 31 i}{2 \cdot 5}

x = \frac{- 17 + 31 i}{2 \cdot 5} : - \frac{17}{10} + i \frac{31}{10}

x = \frac{- 17 - 31 i}{2 \cdot 5} : - \frac{17}{10} - i \frac{31}{10}

The solutions to the quadratic equation are:

x = - \frac{17}{10} + i \frac{31}{10}, x = - \frac{17}{10} - i \frac{31}{10}

3 p^{2} + 9 p - 120 = 0

- 2 x^{2} - 4 x - 1 = 2 x + 4

x^{2} + 3 x + \frac{3}{4} = 0

- 2 (x + 1)^{2} - 5 = - 55

x, x^{2} + 3 x + h = 9 + h

What are the solutions to the equation 5x^2+17x+16=0 ?
The solutions to the equation 5x^2+17x+16=0 are x=-17/10+i(sqrt(31))/(10),x=-17/10-i(sqrt(31))/(10)
Find the zeros of 5x^2+17x+16=0
The zeros of 5x^2+17x+16=0 are x=-17/10+i(sqrt(31))/(10),x=-17/10-i(sqrt(31))/(10)