What are the solutions to the equation -2x^2-4x-1=2x+4 ?

The solutions to the equation -2x^2-4x-1=2x+4 are x=-3/2-i 1/2 ,x=-3/2+i 1/2

Find the zeros of -2x^2-4x-1=2x+4

The zeros of -2x^2-4x-1=2x+4 are x=-3/2-i 1/2 ,x=-3/2+i 1/2

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- 2 x^{2} - 4 x - 1 = 2 x + 4

x = - \frac{3}{2} - i \frac{1}{2}, x = - \frac{3}{2} + i \frac{1}{2}

Solution steps

- 2 x^{2} - 4 x - 1 = 2 x + 4

Move

4

to the left side

- 2 x^{2} - 4 x - 5 = 2 x

Move

2 x

to the left side

- 2 x^{2} - 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

Simplify

(- 6)^{2} - 4 (- 2) (- 5) : 2 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 6 ) - 2 i}{2 ( - 2 )}

x = \frac{- ( - 6 ) + 2 i}{2 ( - 2 )} : - \frac{3}{2} - i \frac{1}{2}

x = \frac{- ( - 6 ) - 2 i}{2 ( - 2 )} : - \frac{3}{2} + i \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} - i \frac{1}{2}, x = - \frac{3}{2} + i \frac{1}{2}

x^{2} + 3 x + \frac{3}{4} = 0

- 2 (x + 1)^{2} - 5 = - 55

x, x^{2} + 3 x + h = 9 + h

(x + 9) (2 x + 1) = 100

6 x^{2} - 24 x = 30

What are the solutions to the equation -2x^2-4x-1=2x+4 ?
The solutions to the equation -2x^2-4x-1=2x+4 are x=-3/2-i 1/2 ,x=-3/2+i 1/2
Find the zeros of -2x^2-4x-1=2x+4
The zeros of -2x^2-4x-1=2x+4 are x=-3/2-i 1/2 ,x=-3/2+i 1/2