What are the solutions to the equation x^2+4x+10=6 ?

The solutions to the equation x^2+4x+10=6 are x=-2

Find the zeros of x^2+4x+10=6

The zeros of x^2+4x+10=6 are x=-2

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x^{2} + 4 x + 10 = 6

x = - 2

Solution steps

x^{2} + 4 x + 10 = 6

Move

6

to the left side

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

p^{2} - 3 p = 0

1.3 x^{2} + 7 x = 0

4 x^{2} - 90 = 10

x, 2 x^{2} + y^{2} + 3 \cdot x \cdot y = 1

x^{2} - 10 x - 1 = 0

What are the solutions to the equation x^2+4x+10=6 ?
The solutions to the equation x^2+4x+10=6 are x=-2
Find the zeros of x^2+4x+10=6
The zeros of x^2+4x+10=6 are x=-2