What are the solutions to the equation (m^2+2m-1)=0 ?

The solutions to the equation (m^2+2m-1)=0 are m=-1+sqrt(2),m=-1-sqrt(2)

Find the zeros of (m^2+2m-1)=0

The zeros of (m^2+2m-1)=0 are m=-1+sqrt(2),m=-1-sqrt(2)

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(m^{2} + 2 m - 1) = 0

m = - 1 + 2, m = - 1 - 2

Decimal Notation

m = 0.41421 \dots, m = - 2.41421 \dots

Solution steps

(m^{2} + 2 m - 1) = 0

Refine

m^{2} + 2 m - 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1) = 22

m_{1, 2} = \frac{- 2 \pm 2 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 2 2}{2 \cdot 1}, m_{2} = \frac{- 2 - 2 2}{2 \cdot 1}

m = \frac{- 2 + 2 2}{2 \cdot 1} : - 1 + 2

m = \frac{- 2 - 2 2}{2 \cdot 1} : - 1 - 2

The solutions to the quadratic equation are:

m = - 1 + 2, m = - 1 - 2

b^{2} = 36

b^{2} = 18

6 x^{2} - 4 x - 26 + 10 x = 5 x^{2} - 26

x^{2} + 12 x + 26 = - 9

x^{2} + \frac{b}{a} x + \frac{c}{a} = 0

What are the solutions to the equation (m^2+2m-1)=0 ?
The solutions to the equation (m^2+2m-1)=0 are m=-1+sqrt(2),m=-1-sqrt(2)
Find the zeros of (m^2+2m-1)=0
The zeros of (m^2+2m-1)=0 are m=-1+sqrt(2),m=-1-sqrt(2)