What are the solutions to the equation 6x^2-4x-26+10x=5x^2-26 ?

The solutions to the equation 6x^2-4x-26+10x=5x^2-26 are x=0,x=-6

Find the zeros of 6x^2-4x-26+10x=5x^2-26

The zeros of 6x^2-4x-26+10x=5x^2-26 are x=0,x=-6

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6 x^{2} - 4 x - 26 + 10 x = 5 x^{2} - 26

x = 0, x = - 6

Solution steps

6 x^{2} - 4 x - 26 + 10 x = 5 x^{2} - 26

Refine

6 x^{2} + 6 x - 26 = 5 x^{2} - 26

Move

26

to the left side

6 x^{2} + 6 x = 5 x^{2}

Move

5 x^{2}

to the left side

x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 \cdot 1}, x_{2} = \frac{- 6 - 6}{2 \cdot 1}

x = \frac{- 6 + 6}{2 \cdot 1} : 0

x = \frac{- 6 - 6}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

x^{2} + 12 x + 26 = - 9

x^{2} + \frac{b}{a} x + \frac{c}{a} = 0

5 x^{2} + 34 x + 24 = 0

x^{2} - 10 x + 25 = 27

x, x^{2} + 2 x y + y^{2} + 2 x - 2 y - 1 = 0

What are the solutions to the equation 6x^2-4x-26+10x=5x^2-26 ?
The solutions to the equation 6x^2-4x-26+10x=5x^2-26 are x=0,x=-6
Find the zeros of 6x^2-4x-26+10x=5x^2-26
The zeros of 6x^2-4x-26+10x=5x^2-26 are x=0,x=-6