What are the solutions to the equation x^2+12x+26=-9 ?

The solutions to the equation x^2+12x+26=-9 are x=-5,x=-7

Find the zeros of x^2+12x+26=-9

The zeros of x^2+12x+26=-9 are x=-5,x=-7

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x^{2} + 12 x + 26 = - 9

x = - 5, x = - 7

Solution steps

x^{2} + 12 x + 26 = - 9

Move

9

to the left side

x^{2} + 12 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 35 = 2

x_{1, 2} = \frac{- 12 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2}{2 \cdot 1}, x_{2} = \frac{- 12 - 2}{2 \cdot 1}

x = \frac{- 12 + 2}{2 \cdot 1} : - 5

x = \frac{- 12 - 2}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 5, x = - 7

x^{2} + \frac{b}{a} x + \frac{c}{a} = 0

5 x^{2} + 34 x + 24 = 0

x^{2} - 10 x + 25 = 27

x, x^{2} + 2 x y + y^{2} + 2 x - 2 y - 1 = 0

x, x^{2} + y^{3} = 2

What are the solutions to the equation x^2+12x+26=-9 ?
The solutions to the equation x^2+12x+26=-9 are x=-5,x=-7
Find the zeros of x^2+12x+26=-9
The zeros of x^2+12x+26=-9 are x=-5,x=-7