What are the solutions to the equation 5x^2+34x+24=0 ?

The solutions to the equation 5x^2+34x+24=0 are x=-4/5 ,x=-6

Find the zeros of 5x^2+34x+24=0

The zeros of 5x^2+34x+24=0 are x=-4/5 ,x=-6

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5 x^{2} + 34 x + 24 = 0

x = - \frac{4}{5}, x = - 6

Decimal Notation

x = - 0.8, x = - 6

Solution steps

5 x^{2} + 34 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 34 \pm 3 4 ^{2} - 4 \cdot 5 \cdot 24}{2 \cdot 5}

3 4^{2} - 4 \cdot 5 \cdot 24 = 26

x_{1, 2} = \frac{- 34 \pm 26}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 34 + 26}{2 \cdot 5}, x_{2} = \frac{- 34 - 26}{2 \cdot 5}

x = \frac{- 34 + 26}{2 \cdot 5} : - \frac{4}{5}

x = \frac{- 34 - 26}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

x = - \frac{4}{5}, x = - 6

x^{2} - 10 x + 25 = 27

x, x^{2} + 2 x y + y^{2} + 2 x - 2 y - 1 = 0

x, x^{2} + y^{3} = 2

2 x^{2} + 2 x + 1

8^{2} + 3^{2} = c^{2}

What are the solutions to the equation 5x^2+34x+24=0 ?
The solutions to the equation 5x^2+34x+24=0 are x=-4/5 ,x=-6
Find the zeros of 5x^2+34x+24=0
The zeros of 5x^2+34x+24=0 are x=-4/5 ,x=-6