What are the solutions to the equation x^2-10x+25=27 ?

The solutions to the equation x^2-10x+25=27 are x=5+3sqrt(3),x=5-3sqrt(3)

Find the zeros of x^2-10x+25=27

The zeros of x^2-10x+25=27 are x=5+3sqrt(3),x=5-3sqrt(3)

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x^{2} - 10 x + 25 = 27

x = 5 + 33, x = 5 - 33

Decimal

x = 10.19615 \dots, x = - 0.19615 \dots

Solution steps

x^{2} - 10 x + 25 = 27

Move

27

to the left side

x^{2} - 10 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 2) = 63

x_{1, 2} = \frac{- ( - 10 ) \pm 6 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6 3}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 6 3}{2 \cdot 1}

x = \frac{- ( - 10 ) + 6 3}{2 \cdot 1} : 5 + 33

x = \frac{- ( - 10 ) - 6 3}{2 \cdot 1} : 5 - 33

The solutions to the quadratic equation are:

x = 5 + 33, x = 5 - 33

x, x^{2} + 2 x y + y^{2} + 2 x - 2 y - 1 = 0

x, x^{2} + y^{3} = 2

2 x^{2} + 2 x + 1

8^{2} + 3^{2} = c^{2}

- k^{2} - 65 k + 720 = 0

What are the solutions to the equation x^2-10x+25=27 ?
The solutions to the equation x^2-10x+25=27 are x=5+3sqrt(3),x=5-3sqrt(3)
Find the zeros of x^2-10x+25=27
The zeros of x^2-10x+25=27 are x=5+3sqrt(3),x=5-3sqrt(3)