What are the solutions to the equation x^2+x-100=0 ?

The solutions to the equation x^2+x-100=0 are x=(-1+sqrt(401))/2 ,x=(-1-sqrt(401))/2

Find the zeros of x^2+x-100=0

The zeros of x^2+x-100=0 are x=(-1+sqrt(401))/2 ,x=(-1-sqrt(401))/2

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x^{2} + x - 100 = 0

x = \frac{- 1 + 401}{2}, x = \frac{- 1 - 401}{2}

Decimal Notation

x = 9.51249 \dots, x = - 10.51249 \dots

Solution steps

x^{2} + x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 100 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 100) = 401

x_{1, 2} = \frac{- 1 \pm 401}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 401}{2 \cdot 1}, x_{2} = \frac{- 1 - 401}{2 \cdot 1}

x = \frac{- 1 + 401}{2 \cdot 1} : \frac{- 1 + 401}{2}

x = \frac{- 1 - 401}{2 \cdot 1} : \frac{- 1 - 401}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 401}{2}, x = \frac{- 1 - 401}{2}

x^{2} - 6 x + 40 = 0

x, 4 x^{2} - 24 x + 64 y^{2} + 2 y + 55 = 0

x, x^{2} + 6 x + 4 = 0

- 4 x^{2} + 20 x - 9 = 0

k^{2} - 36 = 0

What are the solutions to the equation x^2+x-100=0 ?
The solutions to the equation x^2+x-100=0 are x=(-1+sqrt(401))/2 ,x=(-1-sqrt(401))/2
Find the zeros of x^2+x-100=0
The zeros of x^2+x-100=0 are x=(-1+sqrt(401))/2 ,x=(-1-sqrt(401))/2